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Home/ Questions/Q 7798899
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T00:08:01+00:00 2026-06-02T00:08:01+00:00

I’ve been trying to implement trapezoid rule for double integral. I’ve tried many approaches,

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I’ve been trying to implement trapezoid rule for double integral. I’ve tried many approaches, but I can’t get it to work right.

static double f(double x) {
    return Math.exp(- x * x / 2);
}

// trapezoid rule
static double trapezoid(double a, double b, int N) {
    double h = (b - a) / N;
    double sum = 0.5 *  h * (f(a) + f(b));
    for (int k = 1; k < N; k++)
        sum = sum + h * f(a + h*k);
    return sum;
}

I understand the method for a single variable integral, but I don’t know how to do it for a 2D integral, say: x + (y*y).
Could someone please explain it briefly?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T00:08:03+00:00Added an answer on June 2, 2026 at 12:08 am

    If you’re intent on using the trapezoid rule then you would do it like so:

    // The example function you provided.
    public double f(double x, double y) {
        return x + y * y;
    }
    
    /**
     * Finds the volume under the surface described by the function f(x, y) for a <= x <= b, c <= y <= d.
     * Using xSegs number of segments across the x axis and ySegs number of segments across the y axis. 
     * @param a The lower bound of x.
     * @param b The upper bound of x.
     * @param c The lower bound of y.
     * @param d The upper bound of y.
     * @param xSegs The number of segments in the x axis.
     * @param ySegs The number of segments in the y axis.
     * @return The volume under f(x, y).
     */
    public double trapezoidRule(double a, double b, double c, double d, int xSegs, int ySegs) {
        double xSegSize = (b - a) / xSegs; // length of an x segment.
        double ySegSize = (d - c) / ySegs; // length of a y segment.
        double volume = 0; // volume under the surface.
    
        for (int i = 0; i < xSegs; i++) {
            for (int j = 0; j < ySegs; j++) {
                double height = f(a + (xSegSize * i), c + (ySegSize * j));
                height += f(a + (xSegSize * (i + 1)), c + (ySegSize * j));
                height += f(a + (xSegSize * (i + 1)), c + (ySegSize * (j + 1)));
                height += f(a + (xSegSize * i), c + (ySegSize * (j + 1)));
                height /= 4;
    
                // height is the average value of the corners of the current segment.
                // We can use the average value since a box of this height has the same volume as the original segment shape.
    
                // Add the volume of the box to the volume.
                volume += xSegSize * ySegSize * height;
            }
        }
    
        return volume;
    }
    

    Hope this helps. Feel free to ask any questions you may have about my code (warning: The code is untested).

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