Question

Ive been trying to sort out output using AWK, and have been pretty successful going through some of the stuff on stack overflow until i hit the last part of the command below.

-bash-3.2$ find /home/username/www/devdir -mindepth 2 -maxdepth 2 -type d -printf "%TY %Tm %Tb %Td,%TH:%TM,%p,\n" | grep "^$r" | grep Aug | sort -r | awk -F '/' '{print $1,$6","$7}' | awk -F " " '$1, { for (i=3; i<=NF; i++) printf("%s ", $i); printf("\n"); }' | head -10
awk: $1, { for (i=3; i<=NF; i++) printf("%s ", $i); printf("\n"); }
awk:     ^ syntax error

The output looks like the below:

2010 08 Aug 28,11:51, Directory Tom,005,
2010 08 Aug 28,11:50, Directory Smith,004,
2010 08 Aug 28,11:46, Directory Jon,003,

I want it to look like:

2010 Aug 28,11:51, Directory Tom,005,
2010 Aug 28,11:50, Directory Smith,004,
2010 Aug 28,11:46, Directory Jon,003,

I woud like to cut the “08” out of it, and sometimes without losing the sorting done earlier. This will change to 09 next month and 10 the following, I believe I can use sed to solve this, however I am not an expert with it. Can someone shed some light as to what I should do to overcome this obstacle?

I’ve referenced this question to get an idea of what I needed to do: Sorting output with awk, and formatting it

Answer 1

What do want do accomplish exactly with this part?

awk -F " " '$1, { }'

I mean the $1, …

Regarding the update:

sed 's/^\([0-9]\+\) 08 \(.\+\)$/\1 \2/'

should cut this out.

Or more generic:

sed 's/^\([0-9]\+\) [0-9][0-9] \(.\+\)$/\1 \2/'