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Home/ Questions/Q 6648033
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T00:36:29+00:00 2026-05-26T00:36:29+00:00

I’ve been trying to use the pipe() system call to create a shell that

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I’ve been trying to use the pipe() system call to create a shell that supports piping (with an arbitrary number of commands).

Unfortunately, I haven’t had much luck using pipe(). After spending a few days looking at various online resources, I decided to put together an oversimplified program that has the same effect as executing ls | sort to see if I could even get a pipe to work for two sibling, child processes. Here’s the code:

#include <sys/wait.h>
#include <unistd.h>

void run(char *cmd) {
   char *args[2];
   args[0] = cmd;
   args[1] = NULL;

   execvp(cmd, args);
}

int main(void) {
    int filedes[2];
    pipe(filedes);

    pid_t pid_a, pid_b;

    if (!(pid_a = fork())) {
        dup2(filedes[1], 1);
        run("ls");
    }

    if (!(pid_b = fork())) {
        dup2(filedes[0], 0);
        run("sort");
    }

    waitpid(pid_a, NULL, 0);
    waitpid(pid_b, NULL, 0);

    return 0;
}

The pipe is created in the parent and I know that after the execvp() call, each child process inherits the file descriptors that pipe() creates in the parent. For the ls process, I’m using dup2() to redirect its standard out (1) to the write-end of the pipe and for the sort process, standard in (0) is being redirected to the read-end of the pipe.

Finally, I wait for both processes to finish before exiting.

My intuition tells me this should work, but it doesn’t!

Any suggestions?

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  1. Editorial Team
    Editorial Team
    2026-05-26T00:36:29+00:00Added an answer on May 26, 2026 at 12:36 am

    Before calling waitpid in the parent process you have to close all file descriptors from the pipe that you don’t need. These are:

    • filedes[0] in pid_a
    • filedes[1] in pid_b
    • both filedes[0] and filedes[1] in the parent process

    You should also check that pipe() and fork() didn’t return -1, which means an error happened.

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