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Home/ Questions/Q 7036605
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T01:26:39+00:00 2026-05-28T01:26:39+00:00

I’ve been using the Curiously recurring template pattern The general code looks like this:

  • 0

I’ve been using the Curiously recurring template pattern The general code looks like this:

template <typename T> void genericFunction(T &);
template <typename T> struct Functionality {
    void genericMethod() {
        genericFunction(*((T *)this)) ;
    }
};

struct Klass : public Functionality<Klass> {};

void main() {
    Klass obj ;
    obj.genericMethod();
}

template <> void genericFunction<Klass>(Klass &obj) {
    //do stuff with Klass &obj here
}

I ran into an error today which cost me about 90 minutes of hair-pulling fustration, this error was caused by using an incorrect template parameter for my base class inheritance declaration, somewhat like so:

struct Klass : public Functionality<SomeOtherKlass> {}; //SomeOtherKlass wrong!!!

I’d like to enhance my code so that this mismatch between the derived class and the base class template parameter is detected (runtime, compile time, anytime 🙂 ), is this even possible?, thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-28T01:26:39+00:00Added an answer on May 28, 2026 at 1:26 am

    You could assert the relation in e.g. genericMethod() using Boost or C++11 features:

    BOOST_STATIC_ASSERT(( boost::is_base_of<Functionality<T>, T>::value ));
    

    … although that is assuming that the other class doesn’t derive from Functionality<T> as well.

    An alternative could be to assert the relation at runtime in test-builds:

    template <typename T> struct Functionality {
    #ifdef TEST_BUILD
        virtual ~Functionality() {}
    #endif
        void genericMethod() {
    #ifdef TEST_BUILD
            assert(dynamic_cast<T*>(this));
    #endif
            genericFunction(*((T *)this)) ;
        }
    };
    

    Note that the test won’t work inside constructors and destructors

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