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Home/ Questions/Q 9210461
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T01:05:01+00:00 2026-06-18T01:05:01+00:00

I’ve been working on a tiled map renderer, and I’ve tried to make a

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I’ve been working on a tiled map renderer, and I’ve tried to make a seperate Class in another file. I get this error message:

Type Error: 'renderer' object is not callable

Here’s the render.py file:

import pyglet, json
from pyglet.window import key
from pyglet.gl import *
from ConfigParser import SafeConfigParser
from cocos.layer import *
from cocos.batch import *
from cocos.sprite import Sprite

class renderer( Layer ):
    def __init__(self, mapname):
        super( renderer, self ).__init__()
        parser = SafeConfigParser()
        try:
            world = parser.read('maps/'+mapname+'.txt')
            print world
        except IOError:
            print("No world file!")
            return
        layer = json.loads(parser.get('layer1', 'map'))
        tiletype = parser.get('type', 'tile')
        print tiletype
        tilesize = 64

        for x in range(0, len(layer)):
            for y in range(0, len(layer[x])):
                self.spr = Sprite("image/tiles/"+tiletype+"/"+str(layer[x][y])+".png")
                self.spr.position = ((x+1)*tilesize, (y+1)*tilesize)
                self.add(self.spr)

And this is the piece of code I call it with:

from other.render import renderer

 

world = renderer('buildnew')
world()

File Structure:

game/main.py
game/other/render.py

What am I doing wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T01:05:03+00:00Added an answer on June 18, 2026 at 1:05 am
    world = renderer('buildnew')
    world()
    

    First you make an instance of the renderer class and store it to world.
    But then you write world(), which is wrong cause this object is not callable.
    If you want to make world a callable object, you should implement the __call__ method in the renderer class.

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