Question

I’ve been working on HTTLCS and am having some difficulty finishing up the problem.

Solving a problem was not much of an issue, but I have trouble returning my result as a string rather than the tuple data type.

Here is my code:

def wordCount(paragraph):
    splited = paragraph.split()
    wordnum = len(splited)
    eWord = []
    for aWord in splited:
        if "e" in aWord:
            eWord.append(aWord)
    eWordnum = len(eWord)
    percent = round(eWordnum / wordnum * 100,2)
    return "Your text contains", wordnum, "words, of which" , eWordnum , "(" , percent , "%)" , "contains an 'e'." 



print(wordCount(p))

Python outputs ('Your text contains', 108, 'words, of which', 50, '(', 46.3, '%)', "contains an 'e'.") which is a tuple, not a string.

I know I can just put print at the end of the function and call the function without print() statement, but how do I solve this with a return statement?

Answer 1

It’s because you’re using commas in your return statement, which Python is interpreting as a tuple. Try using format() instead:

def wordCount(paragraph):
    splited = paragraph.split()
    wordnum = len(splited)
    eWord = []
    for aWord in splited:
        if "e" in aWord:
            eWord.append(aWord)
    eWordnum = len(eWord)
    percent = round(eWordnum / wordnum * 100,2)
    return "Your text contains {0} words, of which {1} ({2}%) contains an 'e'".format(wordnum, eWordnum, percent)

---

>>> wordCount("doodle bugs")

"Your text contains 2 words, of which 1 (0.0%) contains an 'e'"