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Home/ Questions/Q 6172181
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T23:20:54+00:00 2026-05-23T23:20:54+00:00

I’ve been working on my own javascript library, kis-js. I recently converted it to

  • 0

I’ve been working on my own javascript library, kis-js. I recently converted it to work with dom selectors like jQuery, but because of javascript copying only references I have this issue:

If you call $_ twice, the second time you call it changes the result of the first call.

Test Code:

<h1>Heading</h1>
<a>Anchor</a>
<script>
  var anchor = $_("a");
  var heading = $_("h1");
  console.log(anchor.el); // should be <a>, but it's <h1>
</script>

Here’s the source to the library: https://github.com/timw4mail/kis-js/blob/master/kis.js

I was thinking I needed to create a deep-copy of the constructor object, but I’m not quite sure how to go about that.

Edit:

I created a deep copy function:

dcopy = function(obj)
{
    var type, f;

    if(obj == null)
    {
        return;
    }

    if(typeof Object.create !== "undefined")
    {
        return Object.create(obj);
    }

    var type = typeof obj;

    if(type !== "object" && type !== "function")
    {
        return;
    }

    var f = function(){};

    f.prototype = obj;

    return new f();

};

How can I use this so that I can extend my constructed object?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T23:20:56+00:00Added an answer on May 23, 2026 at 11:20 pm

    So, I just used this function.

    dcopy = function(obj) {
    var type, f;
    
    if(obj == null)
    {
        return;
    }
    
    if(typeof Object.create !== "undefined")
    {
        return Object.create(obj);
    }
    
    var type = typeof obj;
    
    if(type !== "object" && type !== "function")
    {
        return;
    }
    
    var f = function(){};
    
    f.prototype = obj;
    
    return new f();
    
    };
    
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