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Home/ Questions/Q 4028982
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T11:17:18+00:00 2026-05-20T11:17:18+00:00

I’ve been working on this for one hour, just can’t get it. I have

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I’ve been working on this for one hour, just can’t get it.

I have a Vector2d class:

public class Vector2d
{
    public double x = 0.0;
    public double y = 0.0;

    ....
}

This vector class has a rotate() method which is causing me trouble.

The first snippet seems to make the x and y values smaller and smaller. The second one works just fine! Am I missing something simple here?

public void rotate(double n)
{
    this.x = (this.x * Math.cos(n)) - (this.y * Math.sin(n));
    this.y = (this.x * Math.sin(n)) + (this.y * Math.cos(n));
}

This works:

public void rotate(double n)
{
    double rx = (this.x * Math.cos(n)) - (this.y * Math.sin(n));
    double ry = (this.x * Math.sin(n)) + (this.y * Math.cos(n));
    x = rx;
    y = ry;
}

I just can’t spot any difference there

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  1. Editorial Team
    Editorial Team
    2026-05-20T11:17:18+00:00Added an answer on May 20, 2026 at 11:17 am

    The first line sets the value of this.x which is then used in the second line when what you really want is the original value of this.x. The second version works fine because you don’t alter this.x.

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