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Home/ Questions/Q 6021885
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T03:46:41+00:00 2026-05-23T03:46:41+00:00

I’ve clearly established how to make a generic Tuple as follows when the number

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I’ve clearly established how to make a generic Tuple as follows when the number of items is known in advance…

        Type t = typeof(Tuple<,,>);
        Type[] keys = new Type[] { typeof(string), typeof(string), typeof(int) };
        Type specific = t.MakeGenericType(keys);

but what if the number of objects in the “keys” array is variable? How to you start the ball rolling with the initial assignment to “t”?

Cheers.
Craig

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  1. Editorial Team
    Editorial Team
    2026-05-23T03:46:42+00:00Added an answer on May 23, 2026 at 3:46 am

    Personally, I would have an array of the generic type definitions:

    Type[] tupleTypes = {
        typeof(Tuple<>),
        typeof(Tuple<,>),
        typeof(Tuple<,,>),
        typeof(Tuple<,,,>),
        typeof(Tuple<,,,,>),
        typeof(Tuple<,,,,,>),
        typeof(Tuple<,,,,,,>),
        typeof(Tuple<,,,,,,,>),
    };
    

    You could do this in code, but it would be a bit of a pain… probably something like:

    Type[] tupleTypes = Enumerable.Range(1, 8)
                                  .Select(x => Type.GetType("System.Tuple`" + x)
                                  .ToArray();
    

    Or avoiding the array:

    Type generic = Type.GetType("System.Tuple`" + keys.Length);
    Type specific = generic.MakeGenericType(keys);
    
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