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Home/ Questions/Q 9156197
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T12:43:35+00:00 2026-06-17T12:43:35+00:00

I’ve created a C++ structure for reading and verifying header of JFIF file-format. The

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I’ve created a C++ structure for reading and verifying header of JFIF file-format.
The structure is as follows…

#pragma pack(1)
typedef struct _JFIF_Header
{
    WORD SOIMarker;         // start of image marker
    WORD APP0_Marker;       // Application use marker
    WORD APP0_Length;       // Length of APP0 field
    BYTE Identifier[5];     // zero terminating string "JFIF",X'4A', X'46', X'49', X'46', X'00'
    BYTE Version[2];        // X'01',X'02'
    BYTE Units;             // units = 0:no units ;; units = 1:X and Y are dots per inch ;; units = 2:X and Y are dots per cm
    WORD XDensity;          // horizontal pixel density
    WORD YDensity;          // vertical pixel density
    BYTE XThumbnail;        // Thumbnail horizontal pixel density
    BYTE YThumbnail;        // Thumbnail vertical pixel density
}JFIFHeader;

Reading from raw disk clusters and copying these bytes in JFIFHeader Structure has done, and everything works fine.
Now, the problem is, values saved in XDensity and YDensity variables are very high (X:24576,Y:24576 I read an image in Hex-Editor). This value cannot be the actual width and height of the image.
The value of Units is 0x01 , i.e. unit is in “pixels per inch”.

How can I get the actual image resolution 1024x826 from these value ?
If this is not the right method, please give me any other alternative.

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  1. Editorial Team
    Editorial Team
    2026-06-17T12:43:35+00:00Added an answer on June 17, 2026 at 12:43 pm

    You can locate JPEG’s SOF0 marker (0xC0) and it is followed by 16-bit length, and then bits per pixel (8 bit), height (16 bit), width (16-bit) and component count (8 bit). All values are network byte order.

    enter image description here

    Image is 0x1C2 by 0x1C2 pixels (450×450).

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