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Home/ Questions/Q 6333397
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T18:27:15+00:00 2026-05-24T18:27:15+00:00

I’ve created a form and I need the user to enter some info then

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I’ve created a form and I need the user to enter some info then upload a picture.
So lets say I have something like this:

<form method="post" enctype="multipart/form-data" action="some servlet/filter">
<input type="file" name="logo">
</form>

I need to use java to change that data to a byte[] then to blob so I can insert to a table.
How do I get the data from this form?

A bit of info on this:
I created the page using javascript, then when submitted it will call a java function to handle the data from the form. It seems that when I submit the form the data for the file is not passed over to the servlet.

So far the few methods I’ve tried have returned null and I’m outta ideas…

Any examples/help is greatly appreciated!

I think the main question I have is where is the file data stored before the java file start working on it? Is a special global variable holding the data or something like that?

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  1. Editorial Team
    Editorial Team
    2026-05-24T18:27:15+00:00Added an answer on May 24, 2026 at 6:27 pm

    You can use the Apache Commons FileUpload library.

    The Commons FileUpload package makes it easy to add robust, high-performance, file upload capability to your servlets and web applications.

    FileUpload parses HTTP requests which conform to RFC 1867, "Form-based File Upload in HTML". That is, if an HTTP request is submitted using the POST method, and with a content type of "multipart/form-data", then FileUpload can parse that request, and make the results available in a manner easily used by the caller.

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