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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T13:40:04+00:00 2026-06-06T13:40:04+00:00

I’ve created a Google chart and I’ve added data taken from the database itself.

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I’ve created a Google chart and I’ve added data taken from the database itself. When getting data through php loops though, I have had some difficulty because I couldn’t amend that data to the chart because of its syntax.

This is as far as I have gone. I need to get the mysql values in place of:

1170, 460, 45, 123, 456],
660, 1120, 145, 785, 658]

    var data = google.visualization.arrayToDataTable([
      ['Term', <?php

      while ($getchartrows =  mysql_fetch_array($getchart))
      {
          echo  " ' " . $getchartrows['std_ID'] . " ' " . ",";
      }

      ?>],

      <?php


      $one = mysql_query("SELECT * FROM stusitting WHERE std_ID = '0001' AND subjectNo = '$subin' AND grade = '$gradein' AND termNo = '$tcheck' ");
      $getone = mysql_fetch_array($one);

      ?>

          ['01',  <?php echo $getone ['marks']; ?>,      400, 495, 565, 415],
      ['02',  1170,      460, 45, 123, 456],
      ['03',  660,       1120, 145, 785, 658]
    ]);




    var options = {
      title: 'Class Progress'
    };
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T13:40:05+00:00Added an answer on June 6, 2026 at 1:40 pm

    Try to tackle one problem after the other. First, get the data you need from the database. Then, create the data structure you need in PHP, and convert it to JavaScript using json_encode(). Finally, pass it to the visualization function in JavaScript:

    <?php
    // query data
    $result = mysql_query(...);
    
    // format data structure
    $data = array();
    $i = 0;
    while($row = mysql_fetch_array($result)) {
        $i += 1;
        array_push($data, array($i) + $row);
    }
    
    // convert to JavaScript
    ?>
    var raw_data = <?php echo json_encode($data) ?>;
    
    // visualize
    var data = google.visualization.arrayToDataTable(raw_data);
    
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