Question

I’ve created a new class that composes std::deque by private inheritance, i.e,

class B : private std::deque<A>
{ ... };

and in my source code I tried to use iterator of B, i.e.,

B::iterator it

The compiler error is

error C2247: 'std::deque<_Ty>::iterator' not accessible because 'B' uses 'private' to inherit from 'std::deque<_Ty>'

So the question is, how can I make the iterator accessible?

Answer 1

You have to promote this iterator class.

Use using keyword in public section.

class B : private std::deque<A>
{ ... 
 public:
   using std::deque<A>::iterator;    
};

The same for other types as well as other functions from implementation base class(es).