Question

I’ve created a template class that outputs values based on their data types i.e. long gets output as a signed integer (decimal), whereas RESULT gets output in hex format. I defined RESULT as:

typdef long RESULT.

This isn’t working correctly because RESULT is being treated like a long and RESULT‘s output routine never gets called (instead long‘s routine is called). Is there a workaround for this?

Answer 1

What you want will not work for the reasons given.

How about just adding a Function object that formats the output as you want.

class A {
    template< typename T>
    std::string output(long val) {return T(val)}
}

struct decimal {
    std::string operator()(long val) {//return decimal}
}

struct hex {
    std::string operator()(long val) {//return hex}
}

A sample use case:

A a;
cout << a.output<decimal>(10) << endl;
cout << a.output<hex>(10) << endl;