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Home/ Questions/Q 197453
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T16:51:15+00:00 2026-05-11T16:51:15+00:00

I’ve created a Windows service in C#, installed it on a server and it

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I’ve created a Windows service in C#, installed it on a server and it is running fine.

Now I want to install the same service again, but running from a different working directory, having a different config file etc. Thus, I would like to have two (or more) instances of the same service running simultaneously.
Initially, this isn’t possible since the installer will complain that there’s already a service with the given name installed.

I can overcome this by changing my code, setting the ServiceBase.ServiceName property to a new value, then recompiling and running InstallUtil.exe again. However, I would much prefer if I could set the service name at install-time, i.e. ideally I would do something like

InstallUtil.exe /i
/servicename=”MyService Instance 2″
MyService.exe

If this isn’t achievable (I very much doubt it), I would like to be able to inject the service name when I build the service. I thought it might be possible to use some sort of build event, use a clever msbuild or nant trick or something along those lines, but I haven’t got a clue.

Any suggestions would be greatly appreciated.

Thank you for your time.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T16:51:15+00:00Added an answer on May 11, 2026 at 4:51 pm

    I tried accessing a configuration using

    ConfigurationManager.OpenExeConfiguration(string exePath)
    

    in the installer, but couldn’t get it to work.

    Instead I decided to use System.Environment.GetCommandLineArgs() in the installer like this:

    string[] commandlineArgs = Environment.GetCommandLineArgs();
    
    string servicename;
    string servicedisplayname;
    ParseServiceNameSwitches(
        commandlineArgs, 
        out servicename, 
        out servicedisplayname);
    
    serviceInstaller.ServiceName = servicename;
    serviceInstaller.DisplayName = servicedisplayname;
    

    Now I can install my services using

    InstallUtil.exe /i
    InstallableService.dll
    /servicename=”myserviceinstance_2″
    /servicedisplayname=”My Service
    Instance 2″

    I wrote up a more elaborate explanation here.

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