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Home/ Questions/Q 637395
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T20:37:09+00:00 2026-05-13T20:37:09+00:00

I’ve created an Audit table for an ASP.NET MVC application to track key changes

  • 0

I’ve created an Audit table for an ASP.NET MVC application to track key changes and actions. I want to present the contents of this table to authorized users in an easily readable format on the view.

The Audit table is (simplified) like so:

ID (int) | StaffID (int) | Action (string) | Timestamp (datetime)
-----------------------------------------------------------------
1987     | 27            | Delete entry: 9 | 2010-02-22 12:30:12
1988     | 34            | Add user: 912   | 2010-02-22 12:48:19

So far I’ve just been presenting that using the default “List” view in MVC however we’re getting towards the end of development and I’d like to tidy up this view a bit by showing staff names rather than StaffIDs.

Initially, I’m using the approach of creating a “hybrid model” that contains both Audit and Staff and passing that to the view:

public class AuditModel
{
  public AuditModel(List<Audit> AuditEntries, List<Staff> AllStaff)
  {
    this.Audit = AuditEntries;
    this.Staff = AllStaff;
  }

  public List<Audit> Audit { get; private set; }
  public List<Staff> Staff { get; private set; }
}  

[AcceptVerbs("GET")]
public ActionResult ViewAuditTrail()
{
  var Audit = (from a in db.Audits orderby a.Timestamp descending select a).ToList();
  var Staff = (from s in db.Staffs select s).ToList();
  return View(new AuditModel(Audit, Staff));
}

But that leads to messiness in the view:

<%
foreach (var Entry in Model.AuditEntries)
{
  var StaffDetails = Model.AllStaff.Where(s => s.ID == Entry.StaffID).SingleOrDefault();
  /* output HTML */
}
%>

So I guess what I want to do is create a new model with the following attributes:

  • ID (int) – Audit.ID
  • StaffName (string) – Staff.ID [s => s.StaffID == Staff.ID]
  • Action (string) – Audit.Action
  • Timestamp (datetime) – Audit.Timestamp

But I want to do this in the controller and pass it to the view as a ToList() so my view can be cleaner and simpler.

Any tips?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T20:37:09+00:00Added an answer on May 13, 2026 at 8:37 pm

    Okay, so I got adventurous and tried to figure this out myself and I’ve got a solution but I’m not sure how correct it is!

    So, firstly, I created a new class:

    public class AuditEntries
    {
      public int ID { get; set; }
      public string StaffName { get; set; }
      public string Action { get; set; }
      public System.DateTime Timestamp { get; set; }
    }
    

    I then refactored my ViewAuditTrail action to look like so:

    [AcceptVerbs("GET")]
    public ActionResult ViewAuditTrail()
    {
      var Audit = (from a in db.Audits orderby a.Timestamp descending select a).ToList();
    
      var AuditEntry = new List<AuditEntries>();
    
      foreach (var e in Audit)
      {
        var Staff = (from s in db.Staffs where s.ID == e.StaffID select s).SingleOrDefault();
    
        AuditEntries Entry = new AuditEntries();
        Entry.ID = e.ID;
        Entry.StaffName = Staff.Forename + " " + Staff.Surname + " (" + Staff.ID.ToString() + ")";
        Entry.Action = e.Action;
        Entry.Timestamp = e.Timestamp;
    
        AuditEntry.Add(Entry);
      }
    
      return View(AuditEntry.ToList());
    }
    

    And now my ViewAuditTrail view is just a strongly-typed view bound to the AuditEntries class using the default MVC list view type.

    It seems to work fine but I’m sure it can be improved upon – does anyone have any suggestions?

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