Question

I’ve developed a PHP-code that takes in user’s comments and stores them in DB. But I wanted to output the user’s image also when he posts a comment. Also, if there is no image for the user in the DB, then a default image should be shown.
Currently my PHP code looks like:

<?php
if($pid && $sess_uid && $comment_text){
    $sql = "INSERT INTO ttl_comments (comment_pid, comment_text, comment_uid) VALUES ('".$pid."', '".$comment_text."', '".$sess_uid."')";

    $result = mysql_query($sql);
    $comment_id = mysql_insert_id();
    if($comment_id > 0)
    echo '<div class="usercomment">
            <div class="clr"></div>
            <a href="profile.php?uid='.$sess_uid.'"></a>
            <a href="profile.php?uid='.$sess_uid.'">
                <span class="commentsuser">'.$sess_fname." ".$sess_lname.'</span>
            </a>
            <span class="comments">'.$comment_text.'</span>
        </div>
}
?>

Answer 1

you should always store the instance of the image in the DB when working with larger amount of data. One cannot go on naming 1000 images. I guess the following link will help you improve upon it:
store image in database or in a system file?