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Home/ Questions/Q 7666443
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T14:50:03+00:00 2026-05-31T14:50:03+00:00

I’ve done some search here and couldn’t find an answer, so I think it’s

  • 0

I’ve done some search here and couldn’t find an answer, so I think it’s better to ask.
I’m running a little bit expensive algorithm in a simple Java swing application. Let me describe the structure:

In my JPanel run() method:

public void run() {
    while(true) {
        Algorithm alg = new Algorithm(signal);
        new Thread(alg).start();

        //Wait for algorithm to finish 
        signal.await(alg);

        updateInterface();

        Thread.sleep(60L);
    }
}

Algorithm loops through the pixels of a .JPG file, then loops through another large Integer array (length ~ 12000) and returns. There are very no extra expensive calculationslot. I call Thread.sleep(60L) in the Algorithm run() method also.

The udpateInterface() method is very fast, just draw some java.awt.Polygon objects.

Even though I’m calling Thread.sleep(60L), the CPU usage is about 160% on my Mac Book (2.4 GHz Intel Core 2 Duo, Mem 4GB 1067).

Is there a way I can run this without melting my computer? I’m using CountDownLatch as
a wait notify mechanism.

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-31T14:50:04+00:00Added an answer on May 31, 2026 at 2:50 pm

    I would use the following pattern to schedule a repeating task.

    private ScheduledExecutorService executorService = null;
    
    public void start() {
        if (executorService != null && !executorService.isShutdown()) return;
    
        executorService = Executors.newSingleThreadScheduledExecutor();
            executorService.scheduleAtFixedRate(new Runnable() {
                @Override
                public void run() {
                    Algorithm alg = new Algorithm(signal);
                    alg.run();
                    updateInterface();
                }
            }, 0, 60, TimeUnit.MILLISECONDS);
    }
    
    public void stop() {
        if (executorService != null)
            executorService.shutdown();
    }
    
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