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Editorial Team
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Asked: 2026-06-05T16:45:58+00:00

I’ve got a big solution with many projects in it. So when it builds

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I’ve got a big solution with many projects in it. So when it builds it copies many libraries to the build’s output directory. How can I specify some DLL file’s output directory?

For example:

./OutputDir/Libraries/[and here we have some DLL files]

./OutputDir/Program.exe.

An XCOPY post-build action helps me to copy all DLL files into another directory. Here it is post-build action:

mkdir "$(ProjectDir)bin\$(ConfigurationName)\Libraries"

xcopy "$(ProjectDir)bin\$(ConfigurationName)\*.dll" "$(ProjectDir)bin\$(ConfigurationName)\Libraries"

How should I link those DLL files to an executeable?

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1 Answer

  1. Editorial Team

    You can set output file at project settings or you can overwrite that at build time with /property:OutputDir=OutputDir\Libraries.

    If you need a copy of a dll you can do it with a post build action.

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