I’ve got a class, which has three overloaded methods. Let’s say, there is:
class MyChildClass
{
public void myMethod(int i)
{ /* do something with i */ }
public void myMethod(int a, string b)
{ /* get i from a and b and call: */ myMethod(i); }
public void myMethod(string c, string d)
{ /* get i from c and d and call: */ myMethod(i); }
}
Now I’d like this class to be a private field in other (parent) class, but I need those three methods to be accessible. For now, I just did:
class MyBaseClass
{
private MyChildClass myObject = new myChildClass(); // or similar
public void myMethod(int i)
{ myObject.myMethod(i); }
public void myMethod(int a, string b)
{ myObject.myMethod(a, b); }
public void myMethod(string c, string s)
{ myObject.myMethod(c, d); }
}
Is there a way to implement it as one short method? Something which would look like:
public void myMethod(unknownListOfArgumentsOfDifferentTypes args)
{ myObject.myMethod(args); }
I tried to use public void myMethod(params object[] something) but it didn’t work. Is it possible, or do I have to “project” every method into another?
EDIT: Child class has various methods and fields, which I want to be accessible for parent class only. That’s why I don’t want parent to derive after it. I didn’t explain that, sorry if it looked like child class contains only those three methods. Those are the methods I want to be accessible as public methods of parent class.
You can use
public void myMethod(params object[] something)as in: