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Home/ Questions/Q 6117049
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T15:16:35+00:00 2026-05-23T15:16:35+00:00

I’ve got a contentType (product) that has a taxonomy field (features). The taxonomy term

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I’ve got a contentType (product) that has a taxonomy field (features). The taxonomy term (product feature term) has been customized to include an image field and a description field.

I’d like for the product detail view to display the image from the term along with the name, but I can’t find the property to access it.

I’ve created the following:

Taxonomy

  1. ProductFeature Taxonomony
    • Vocabulary: Feat1, Feat2, Feat3

ContentTypes

  1. Product

    • Fields: Features(Taxonomy)
  2. Product Features Term

    • Fields: Description(Html), Image(Image)

Views

Fields.Contrib.TaxonomyField-Features.cshtml

<!-- Old Code -->
@if (Model.Terms.Count > 0) {
<p class="taxonomy-field">
    <span class="name">@name.CamelFriendly():</span> 
    @(new HtmlString( string.Join(", ", terms.Select(t => Html.ItemDisplayLink(Html.Encode(t.Name), t.ContentItem ).ToString()).ToArray()) ))
</p>
}

<!-- New Code -->
@if (Model.Terms.Count > 0)
{
    <div>
        @foreach (var myTerm in Model.Terms)
        {   
            @Display(???)
        }
    </div>
}

What do replace the question marks with? I’d thought it’d be myTerm.Image but that field doesn’t exist on the dynamic object.

I’ve attached an image of the designer viewer.

enter image description here

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T15:16:35+00:00Added an answer on May 23, 2026 at 3:16 pm

    As Sebastien helped me figure out over on http://orchardtaxonomies.codeplex.com/discussions/263844

    Below is what ended up working.

    (The key bit being: contentField = myTerm.ContentItem.Features.TermImage;)

    @foreach (var myTerm in Model.Terms)
    {
        var contentField = myTerm.ContentItem.Features.TermImage;
        if (!String.IsNullOrWhiteSpace(contentField.FileName)) {
            <p class="image-field">
               <img src="@Url.Content(contentField.FileName)" alt="@contentField.AlternateText" width="@contentField.Width" height="@contentField.Height"/>
            </p>
        }
    }
    
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