Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7218789
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 28, 20262026-05-28T21:31:48+00:00 2026-05-28T21:31:48+00:00

I’ve got a find_by_sql statement which I’m trying to pass the location id to.

  • 0

I’ve got a find_by_sql statement which I’m trying to pass the location id to. I thought I could do something like this:

  def self.location_history()
        Location.find_by_sql("select * from locations a INNER JOIN hotspots b ON a.id = b.location_id INNER JOIN accounts c ON b.mac = c.account_id WHERE a.location_id= '#{id}'")
  end

I figured the following would pull the id parameter from the url:

 a.location_id = '#{id}'

However that throws an error about an undefined variable.

I can see the id => ‘2’ parameter being send with the request but I don’t know how to call from the model. If at all possible?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-28T21:31:48+00:00Added an answer on May 28, 2026 at 9:31 pm

    You cannot access the “params” hash from a Rails model. Params are only for your controller and views to interact.

    You can pass the value you need from the controller to the model with something like this instead:

    def self.location_history(location_id)
      Location.find_by_sql("select * from locations a INNER JOIN hotspots b ON a.id = b.location_id INNER JOIN accounts c ON b.mac = c.account_id WHERE a.location_id= '#{location_id}'")
    end
    

    and in controller:

    def index
      @location_history = Location.location_history(params[:id])
    end
    

    Or better yet, something like this in Rails 3 is way cleaner. Also, this will escape the location_id parameter from SQL injection.

    def self.location_history(location_id)
      joins(:hotspots, :accounts).where(:location_id => location_id)  
    end
    

    You do not need “Location” at the beginning because that is the current model. If your associations are correct, you can use the “joins” scope to link these tables and just pass the parameter you need to “where”,

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
For some reason, after submitting a string like this Jack’s Spindle from a text
I am trying to understand how to use SyndicationItem to display feed which is
I've got a string that has curly quotes in it. I'd like to replace
I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
I'm trying to create an if statement in PHP that prevents a single post
I have some data like this: 1 2 3 4 5 9 2 6
link Im having trouble converting the html entites into html characters, (&# 8217;) i
I would like to count the length of a string with PHP. The string
I used javascript for loading a picture on my website depending on which small

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.