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Home/ Questions/Q 5929395
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T14:24:58+00:00 2026-05-22T14:24:58+00:00

I’ve got a google news feed I display in my WordPress site, using the

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I’ve got a google news feed I display in my WordPress site, using the following code:

$feed = fetch_feed($rss_url); // specify the source feed
$limit = $feed->get_item_quantity(20); // specify number of items
$items = $feed->get_items(0, $limit); // create an array of items
foreach ($items as $item) : 
    echo $item->get_description(); 
endforeach;

Problem is, certain individual articles I need to filter out. Google news items have guid tags. Given the guid of the item, how can I tell SimplePie to ignore the given item?

Thanks-

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  1. Editorial Team
    Editorial Team
    2026-05-22T14:24:58+00:00Added an answer on May 22, 2026 at 2:24 pm

    SimplePie does not have built-in filtering functions (yet). However, you can selectively show only the items you wish:

    $feed = fetch_feed($rss_url); // specify the source feed
    $limit = $feed->get_item_quantity(20); // specify number of items
    $items = $feed->get_items(0, $limit); // create an array of items
    $ignoreGUIDs = array("http://example.com/feed?id=1", "http://example.com/feed?id=2");
    foreach ($items as $item) : 
        if(!in_array($item->get_id(false), $ignoreGUIDs)){
            echo $item->get_description();
        }
    endforeach;
    

    The get_id() method returns an array of the item’s <guid>, <link>, and <title> tags, each of which the in_array() clause then searches for a match of each of your $ignoreGUIDs. If there are no matches, it means the item’s GUID is not in your exlusion list and so the item is shown (by echo).

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