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Home/ Questions/Q 7563527
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T13:41:18+00:00 2026-05-30T13:41:18+00:00

I’ve got a grid with dropdown in every row and I need to render

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I’ve got a grid with dropdown in every row and I need to render it’s state from DB.
So I’ve got dropdowns defined like that with selected option specified for preselecting the value from DB.

<select id='selectId'>
<option value='1'>Option 1</option>
<option value='2' selected='selected'>Option 2</option>
<option value='3'>Option 3</option>
</select>​

The problem is in that when I change the value of a dropdown defined like that in a browser it changes on UI but selected attribute don’t move and stays where it was.
So when I then call $(“#selectId”).val() I get the old one value.

What’s the appropriate way to initialize dropdown control and then have an ability to freely change it’s value in browser or by jQuery?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T13:41:19+00:00Added an answer on May 30, 2026 at 1:41 pm

    This seems to be working fine (Firefox on Ubuntu):

    HTML

    <select id='selectId'>
    <option value='1'>Option 1</option>
    <option value='2' selected='selected'>Option 2</option>
    <option value='3'>Option 3</option>
    </select>
    

    JS

    $('#selectId').change(function() {
        var opt = $(this).find('option:selected');
        console.log([opt.val(), opt.text()]);   
    });
    
    var opt_sel = $('#selectId option:selected');
    opt_sel.val(99);
    opt_sel.text('Changed option');
    

    If you select the options, you’ll see that it will print the changed version. Working example:

    • http://jsfiddle.net/vm4Q8/

    Hope this helps.

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