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Home/ Questions/Q 972099
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T03:04:05+00:00 2026-05-16T03:04:05+00:00

I’ve got a particular function I want to run once, and only after the

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I’ve got a particular function I want to run once, and only after the completion of several AJAX requests.

My current solution looks a bit like this:

function doWork() {
    //This is the function to be run once after all the requests
}

//some tracking/counting variables
var ajaxDoneCounter = 0;
var numOfAjaxRequests = 5;
var workDone = false;

function doWorkTrigger() {
    ajaxDoneCounter++;
    if( !workDone && ajaxDoneCounter >= numOfAjaxRequests ) {
        workDone = true;
        doWork();
    }
}

// ...

//and a number of ajax requests (some hidden within functions, etc)
//they look something like this:
$.ajax({
    url: "http://www.example.com",
    dataType: "json",
    success: function( data ) {
        //load data in to variables, etc
        doWorkTrigger();
    }
});

One obvious pitfall in the above is that any AJAX call that is not successful will not increment ajaxDoneCount and so doWork() will probably never be called. I can get around that using the error callback in inside any $.ajax, so that doesn’t worry me too much.

What I want to know is whether the above is safe and/or good practice?
Is there a trick I’ve missed, or any thing else that might work better?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T03:04:06+00:00Added an answer on May 16, 2026 at 3:04 am

    Update: Since jQuery 1.5, deferred objects [docs] provide a cleaner solution. Have a look at an example here.


    I would use .ajaxComplete(), it will be triggered whenever an Ajax call completed (success or error):

    var numOfAjaxRequests = 5;
    
    $(document).ajaxComplete(function() {
        numOfAjaxRequests--;
        if(!numOfAjaxRequests) {
            doWork();
    
        }
    });
    

    Then you don’t have to edit every Ajax request.

    You could even use .ajaxSend() to get notified of starting Ajax requests, instead of hardcoding it (but I am not sure whether this really works, maybe you will experience race conditions):

    var numOfAjaxRequests = 0;
    
    $(document).ajaxSend(function() {
        numOfAjaxRequests++;
    });
    
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