Question

I’ve got a pretty good working snippit of code, but I was wondering if anyone has any better suggestions on how to do this:

val = ''.join([c for c in val if c in '1234567890.'])

What would you do?

Answer 1

You can use a regular expression (using the re module) to accomplish the same thing. The example below matches runs of [^\d.] (any character that’s not a decimal digit or a period) and replaces them with the empty string. Note that if the pattern is compiled with the UNICODE flag the resulting string could still include non-ASCII numbers. Also, the result after removing “non-numeric” characters is not necessarily a valid number.

>>> import re
>>> non_decimal = re.compile(r'[^\d.]+')
>>> non_decimal.sub('', '12.34fe4e')
'12.344'