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Home/ Questions/Q 8144275
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T13:20:03+00:00 2026-06-06T13:20:03+00:00

I’ve got a public List<FriendProfile> friends = new ArrayList<FriendProfile>(); . I initialize the friends

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I’ve got a public List<FriendProfile> friends = new ArrayList<FriendProfile>();. I initialize the friends list by reading the information from the server. The FriendProfile object contains a int called private int userPosition;

Once the friends list has been initialized, I would like to sort the friends list by having the FriendProfile object with the highest userPosition at index 0 of the list and then sort by accordingly, index 1 with the second highest userPosition …

I guess I could write an sorting algorithm, yet I’m looking for prewritten code (maybe the JDK has some methods to offer?)

Help is appreciated!

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  1. Editorial Team
    Editorial Team
    2026-06-06T13:20:05+00:00Added an answer on June 6, 2026 at 1:20 pm

    Use Collections.sort() and specify a Comparator:

    Collections.sort(friends,
                     new Comparator<FriendProfile>()
                     {
                         public int compare(FriendProfile o1,
                                            FriendProfile o2)
                         {
                             if (o1.getUserPosition() ==
                                     o2.getUserPosition())
                             {
                                 return 0;
                             }
                             else if (o1.getUserPosition() <
                                          o2.getUserPosition())
                             {
                                 return -1;
                             }
                             return 1;
                         }
                     });
    

    or have FriendProfile implement Comparable<FriendProfile>.

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