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Home/ Questions/Q 8090835
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T19:51:19+00:00 2026-06-05T19:51:19+00:00

I’ve got a simple function script, the last line of which is to call

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I’ve got a simple function script, the last line of which is to call the function

fun<-function(){
    readline("This is a test")
    x<-c(4,5)
    y<-c(5,6)
    add<-x+y
    sub<-x-y
    return(list(add,sub))
}

fun()

If I copy this into my R console I get what is to be expected

This is a test
[[1]]
[1]  9 11

[[2]]
[1] -1 -1

But I have been trying to use “source” to automatically pull up my scripts. If I try and use source

source("/Users/Me/Desktop/R.test.R")

I loose my output. I still get the readline, but I loose the return data so I just get this:

This is a test

I can still use source command to access my function if I delete the last line, and then manually type in “fun()”

source("/Users/Me/Desktop/R.test.R")
fun()

but I’d like to make this a one step deal.

Can someone explain why the difference between a “cut and paste” vs using source, and how I use source to call my functions in one step?

Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T19:51:20+00:00Added an answer on June 5, 2026 at 7:51 pm

    When you type things directly in the console, R by default calls print on that object in order to display it. But it only does that directly in the console.

    Try setting print.eval = TRUE when you call source. To see what’s going on, try it both ways with this script:

    fun<-function(){
        readline("This is a test")
        x<-c(4,5)
        y<-c(5,6)
        add<-x+y
        sub<-x-y
        return(list(add,sub))
    }
    
    fun()
    
    x <- 5
    x
    

    Now it’s a little more explicit. Just typing x at the console silently causes R to print it. If you want that behavior when sourcing, you have to say so.

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