Question

I’ve got a String class. Recently, I found the poor thing couldn’t handle:

String string = "Hello World";  

I immediately decided to rectify this by adding a constructor. However, the exact parameter eludes me:

inline String(const char[] str) : Array(str, sizeof(str) / sizeof(char)) { }  

generates the following error: “error C2146: syntax error : missing ‘)’ before identifier ‘str'”

What I’m thinking is that since it’s a static char * literal, it isn’t meant to be passed to a function. But, I don’t actually know.

Thanks. (To reassure – Any array passed to Array will promptly be copied, not stored)

Answer 1

Simplest would be to take const char* as the parameter. Then use strlen to find the string length, then allocate len+1 characters using new and use strncpy to copy the string to the newly allocated memory. BTW, any specific reason not to use std::string?