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Home/ Questions/Q 3276340
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T19:14:49+00:00 2026-05-17T19:14:49+00:00

I’ve got a string looks like this ABC(a =2,b=3,c=5,d=5,e=Something) I want the result to

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I’ve got a string looks like this

ABC(a =2,b=3,c=5,d=5,e=Something)

I want the result to be like

ABC(a =2,b=3,c=5)

What’s the best way to do this? I prefer to use regular expression in Python.

Sorry, something changed, the raw string changed to

ABC(a =2,b=3,c=5,dddd=5,eeee=Something)
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  1. Editorial Team
    Editorial Team
    2026-05-17T19:14:49+00:00Added an answer on May 17, 2026 at 7:14 pm

    Non regex

    >>> s="ABC(a =2,b=3,c=5,d=5,e=Something)"
    >>> ','.join(s.split(",")[:-2])+")"
    'ABC(a =2,b=3,c=5)'
    

    If you want regex to get rid always the last 2

    >>> s="ABC(a =2,b=3,c=5,d=5,e=6,f=7,g=Something)"
    >>> re.sub("(.*)(,.[^,]*,.[^,]*)\Z","\\1)",s)
    'ABC(a =2,b=3,c=5,d=5,e=6)'
    
    >>> s="ABC(a =2,b=3,c=5,d=5,e=Something)"
    >>> re.sub("(.*)(,.[^,]*,.[^,]*)\Z","\\1)",s)
    'ABC(a =2,b=3,c=5)'
    

    If its always the first 3,

    >>> s="ABC(a =2,b=3,c=5,d=5,e=Something)"
    >>> re.sub("([^,]+,[^,]+,[^,]+)(,.*)","\\1)",s)
    'ABC(a =2,b=3,c=5)'
    
    >>> s="ABC(q =2,z=3,d=5,d=5,e=Something)"
    >>> re.sub("([^,]+,[^,]+,[^,]+)(,.*)","\\1)",s)
    'ABC(q =2,z=3,d=5)'
    
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