Question

I’ve got a structure which holds names and ages.
I’ve made a linked-list of these structures, using this as a pointer:

aNode *rootA;

in my main.
Now i send **rootA to a function like so

addElement(5,"Drew",&rootA);

Because i need to pass rootA by reference so that I can edit it in other functions (in my actual program i have two roots, so return will not work)

The problem is, in my program, i can’t say access the structure members.

*rootA->age = 4;

for example doesnt work.

Hopefully you guys can help me out.
Thanks!

Answer 1

It’s hard to tell from your question but it looks like the type of rootA in the last sample is aNode**. If so the reason why it’s failing is that -> has higher precedence than *. You need to use a paren to correct this problem

(*rootA)->age = 4;

See full C Operator Precedence Table.

If the type of rootA is instead aNode*. Then you don’t need to dereference in addition to using ->. Instead just use -> directly

rootA->age = 4;