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Home/ Questions/Q 7712609
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T01:40:29+00:00 2026-06-01T01:40:29+00:00

I’ve got a table in which there are some columns with big text data.

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I’ve got a table in which there are some columns with big text data. The query for 10 rows (table has only 31 records) takes more than 20 seconds. If I remove fields with big size, the query is executed quickly. The query for 1 row (by id) always executed quickly.

How can I do the query for many rows work more faster?

The query looks like this

SELECT DISTINCT (a.id), a.field_1, a.field_2, a.field_3
    , a.field_4, a.field_5, a.filed_6, ...  
FROM table_a a, table_b b 
WHERE a.field_8 = 'o'  
ORDER BY a.field_2 DESC 
LIMIT 10;
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T01:40:30+00:00Added an answer on June 1, 2026 at 1:40 am

    @a_horse already hinted at the likely syntax error. Try:

    SELECT DISTINCT ON (a.id)  a.id, a.field_1, a.field_2, a.field_3, ...
    FROM   table_a a
    -- JOIN table_b b ON ???
    WHERE  a.field_8 = 'o'  
    ORDER  BY a.id, a.field_2 DESC 
    LIMIT  10;
    

    Note the bold emphasis and read up on the DISTINCT clause in the manual.

    Also, an index on field_8 might help.
    A multicolumn index on (field_8, id, field_2) might help even more, if you can narrow it down to that (and if that is the sort order you want, which I doubt).

    If you want the result sorted by a.field_2 DESC first:
    In PostgreSQL 9.1, if id is the primary key:

    SELECT a.id, a.field_1, a.field_2, a.field_3, ...
    FROM   table_a a
    -- JOIN table_b b ON ???
    WHERE  a.field_8 = 'o'
    GROUP  BY a.id   -- primary key takes care of all columns in table a
    ORDER  BY a.field_2 DESC 
    LIMIT  10;
    
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