Question

i’ve got a table like that :

Article Number  Last Voucher Number Last Voucher Date
0557934         519048                  04/02/2005
0557934         519067                  04/02/2005
0557934         528630                  09/29/2005
0557934         528631                  09/29/2005
0557934         529374                  10/13/2005
0557934         529375                  10/13/2005
0557934         529471                  10/16/2005
0557934         529472                  10/16/2005
0557934         535306                  01/08/2006
0557934         535307                  01/08/2006
0557934         1106009                 08/10/2006
0557934         1106010                 08/10/2006
0022738         22554                   02/20/1995
0022738         22595                   03/12/1995
0022738         22597                   03/15/1995
0022738         22605                   03/19/1995
0022738         22616                   03/25/1995
0022738         22621                   03/28/1995
0022738         22630                   04/05/1995

I would like to have only the record with the last date :

Article Number  Last Voucher Number Last Voucher Date
0557934         1106010                 08/10/2006
0022738         22630                   04/05/1995

I can do directly on SQL or on Linq.

Any idea?

Ju

Answer 1

The simplest way is probably using row_number. This also breaks ties for the same voucher date:

select *
from (
    select 
        *
    ,   row_number() over (partition by [Article Number] 
          order by [Last Voucher Date] desc, [Last Voucher Number] desc) as RowNr
    from YourTable
) as SubQueryAlias
where RowNr = 1

Another option is a where not exists clause:

select *
from YourTable yt
where not exists (
    select *
    from YourTable yt2
    where yt.[Article Number] = yt2.[Article Number]
    and yt.[Last Voucher Date] < yt2.[Last Voucher Date]
)

In case of ties for the latest voucher date, this would return both rows.