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Home/ Questions/Q 381287
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T15:04:15+00:00 2026-05-12T15:04:15+00:00

I’ve got a TCP server and client written in C that opens up a

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I’ve got a TCP server and client written in C that opens up a connection that should be open forever. On the first send, errno returns 0 which is fine. On subsequent sends it gives me an errno 60 which is that the operation timed out. The packet is still recieved by the server though and nothing seems to be wrong. What could cause the the errno being set? Is it best to just ignore this error since it seems to be working correctly?

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  1. Editorial Team
    Editorial Team
    2026-05-12T15:04:16+00:00Added an answer on May 12, 2026 at 3:04 pm

    Random guess: errno is only set when a function fails. If the function does not fail, errno is left as-is. It is not set to 0. The following is wrong:

    send( … );
    if (errno) {
        perror("send");
    }
    

    Instead, you must check the result of send:

    ssize_t res = send( … );
    if (-1 == res) {
        perror("send")
    }
    

    You can confirm this with the following program:

    #include <stdio.h>
    #include <unistd.h>
    
    int main() {
        char buf[16];
        ssize_t res;
    
        read(999, buf, sizeof(buf));
        perror("read");
    
        write(1, "hello world\n", 12);
        perror("write");
    }
    

    which outputs:

    read: Bad file descriptor
    hello world
    write: Bad file descriptor
    

    (Note: assuming STDOUT is fd 1)

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