Question

I’ve got a XML Schema (xsd file) snippet bellow, in which I want the NAME and ADRESS elements to appear in any order, but always before the FILM sequence.

So I’ve been trying to do like this :

  <xs:element name="ROOM">
    <xs:complexType>
      <xs:all>
        <xs:element ref="NAME"/>
        <xs:element ref="ADRESS"/>
      </xs:all>
      <xs:sequence>
        <xs:element maxOccurs="unbounded" ref="FILM"/>
      </xs:sequence>
      <xs:attribute name="group" type="xs:NCName"/>
      <xs:attribute name="typ" use="required" type="xs:NCName"/>
    </xs:complexType>
  </xs:element>

I know that the <xs:all> tag cannot be part of an element with other elements at the same child-level … but can’t find a way out …

Any suggestions ? Thanks in advance !

Answer 1

Ok, looks like I’ve found a way eventually :

  <xs:element name="ROOM">
    <xs:complexType>

      <xs:choice>
        <xs:sequence>
          <xs:element ref="NAME"/>
          <xs:element ref="ADRESS"/>
          <xs:element maxOccurs="unbounded" ref="FILM"/>
        </xs:sequence>
        <xs:sequence>
          <xs:element ref="ADRESS"/>
          <xs:element ref="NAME"/>
          <xs:element maxOccurs="unbounded" ref="FILM"/>
        </xs:sequence>
      </xs:choice>

      <xs:attribute name="group" type="xs:NCName"/>
      <xs:attribute name="typ" use="required" type="xs:NCName"/>
    </xs:complexType>
  </xs:element>

But I assume that it’s not very optimized, considering that if you want to do this with 10 elements, you have to specify all permutations …