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Home/ Questions/Q 6679355
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T04:20:59+00:00 2026-05-26T04:20:59+00:00

I’ve got an interface with some generic methods, and I wanted to implement a

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I’ve got an interface with some generic methods, and I wanted to implement a method with overloads to either accept an instance of a class, or its PK value (which is either an int or GUID but does vary).

I added to methods similar to these examples:

    void DoSomething<TKey>(TKey key) where TKey: struct;
    void DoSomething<TModel>(TModel model) where TModel : class;

The ‘DoSomething’ method name on the second of these is highlighted, and the error is

Type ‘ISomeStuff’ already defines a member called ‘DoSomething’ with
the same parameter types.

I’m surprised by this as I’ve clearly defined by parameters to be of different type: one is a class and the other a struct.

Why isn’t this sufficient to make the signatures different?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T04:21:00+00:00Added an answer on May 26, 2026 at 4:21 am

    Jon Skeet has an answer to everything: click me

    quote:

    the declarations only differ in generic constraints, and constraints
    aren’t part of the signature

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