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Home/ Questions/Q 6865515
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T03:03:41+00:00 2026-05-27T03:03:41+00:00

I’ve got in my project code similar to this @Transactional(readOnly = true) public void

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I’ve got in my project code similar to this

@Transactional(readOnly = true)
public void tt() {
    dd();
}

@Transactional()
public void dd() {
    gg();
}

@Transactional(readOnly = true)
public void gg() {

}

Function dd is used both by other readonly transaction functions and not readonly functions. Assuming that transaction should extendend from execution of tt to gg – operations in dd will in be read-only transaction or not?

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  1. Editorial Team
    Editorial Team
    2026-05-27T03:03:42+00:00Added an answer on May 27, 2026 at 3:03 am

    Spring’s AbstractPlatformTransactionManager has a property named validateExistingTransaction that controls this behavior. Javadoc states that:

    When participating in an existing transaction (e.g. with PROPAGATION_REQUIRES or PROPAGATION_SUPPORTS encountering an existing transaction), this outer transaction’s characteristics will apply even to the inner transaction scope. Validation will detect incompatible isolation level and read-only settings on the inner transaction definition and reject participation accordingly through throwing a corresponding exception.

    Since default propagation for Spring @Transactional annotation is REQUIRED and default validation strategy is false, I expect Spring to use existing transaction created from tt method call in readonly mode.

    If you want to have a read only transaction, then you have to annotate your method with:

      @Transactional(propagation=Propagation.REQUIRES_NEW, readOnly=true)
    
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