Question

I’ve got just a quick little poll and a query to check and see if the IPaddress is already in the table to know if someone has already voted. I have the table created already and it works.

My question is with the if else statement it is not working. I am trying to make it

if ip address is in the table show string
else show poll

$ip=$_SERVER['REMOTE_ADDR'];

include("../db/config.php");
include("../db/opendb.php");

$result = mysql_query("SELECT * FROM Poll WHERE ip='$ip'");

if ($result==$ip) {
    echo "Thank you for voting.";
} else {
    echo "<form action=logvote.php method=post>" .
         "<input type=radio name=ans value=ans1> Answer1<br>" .
         "<input type=radio name=ans value=ans2> Answer2<br>" .
         "<input type=radio name=ans value=ans3> Answer3<br>" .
         "<input type=radio name=ans value=ans4> Answer4<br>" .
         "<input type=submit value=Submit>";

    echo "<input type=hidden name=ip value=";   
    echo "$ip>";

    echo "</form>";

 include("../db/closedb.php");

}

Thanks in advance.

Answer 1

Your code should be:

$query = mysql_query("SELECT ip FROM Poll WHERE ip='$ip'");
$info = mysql_fetch_object($query);
$result = $info->ip;

if($result == $ip)

mysql_query() returns a reference not a string.

Also, using ip in the SELECT statement will speed up your code.