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Home/ Questions/Q 3627242
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T23:51:49+00:00 2026-05-18T23:51:49+00:00

I’ve got many files with variables in them like {$var1} some text {$var2} some

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I’ve got many files with variables in them like

{$var1} some text {$var2} some other text

I’d like to give them to awk so that awk extracts them and gives a result like this:

file_name.htm - 8 : {$title}
file_name.htm - 10 : {$css_style}
file_name.htm - 33 : {$img_carte_image_02_over}

This is a piece of cake with this awk script:

#!/usr/bin/gawk -f
BEGIN { }
match($0, /({.*\$.+})/, tab) {
  for (x=1; tab[x]; x++) {
    print FILENAME" - "FNR" : "substr($0, tab[x, "start"], tab[x, "length"])
  }
}
END { }

I’m calling it like this:

find website/ | grep -E '(html|htm)$' | xargs ./myh.sh | more

Everything works fine except when multiples variables are on the same line. In this case I get:

file_name.htm - 59 : {$var1}<br/>{$var2}

whereas I want:

file_name.htm - 59 : {$var1}
file_name.htm - 59 : {$var2}

Any idea how I could/should do?
Of course if you have another solution (with sed or whatever) it’s ok for me!

Thanks a lot!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T23:51:49+00:00Added an answer on May 18, 2026 at 11:51 pm

    Try this one:

    awk '{
        line=$0; 
        while (match(line,/({[^$]*\$[^}]+})/)){
            print FILENAME,"-",FNR,":",substr(line,RSTART,RLENGTH);
            line=substr(line,RSTART+RLENGTH+1)
        }
    }'
    

    The cycle ends when match() returns 0, that is when line doesn’t contain any other “{foo$bar}” strings; I used substr() to remove the part of the line which has been already scanned for matches.

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