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Home/ Questions/Q 3974814
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T04:36:44+00:00 2026-05-20T04:36:44+00:00

I’ve got reporting of a user’s score every time it happens. Now I want

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I’ve got reporting of a user’s score every time it happens. Now I want to show the best score a user has had. The table set up is like this:

Player(id, name)

PlayerHasAchievement(id, playerId,
achievementId)

Achievement(id, type, amount, time)

This is what I have right now:

SELECT MAX(ach.amount) as amount, p.username, ach.time
FROM  achievement as ach
INNER JOIN playerHasAchievement as playAch ON ach.id = playAch.id
INNER JOIN player as p ON p.userId = playAch.userid
WHERE ach.type = 2
GROUP BY amount
ORDER by `amount` DESC
LIMIT $amount

I tried to select it distinctly but it didn’t work.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T04:36:44+00:00Added an answer on May 20, 2026 at 4:36 am

    The problem is the the ach.time you are getting is not the same row as the MAX(amount). Join another subquery to get the MAX(amount) first.

    Note: In the table definitions you posted, playerHasAchievement has a field playerId not userId

    SELECT MAX(ach.amount) as amount, p.username, MAX(ach.time) MaxTime
    FROM  achievement as ach
      INNER JOIN playerHasAchievement as playAch ON ach.id = playAch.id
      INNER JOIN player as p ON p.userId = playAch.playerId
      INNER JOIN (
        SELECT playAch.playerId, MAX(ach.amount) as MaxAmount
        FROM  achievement as ach
          INNER JOIN playerHasAchievement as playAch ON ach.id = playAch.id
        WHERE ach.type = 2
        GROUP BY playAch.playerId
      ) g ON p.playerId = g.playerId AND ach.amount = g.MaxAmount
    WHERE ach.type = 2
    GROUP BY p.playerId
    ORDER by `amount` DESC
    LIMIT $amount";
    

    The reason why we group the outer query, is to avoid ties – say a player had the same score twice.

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