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Home/ Questions/Q 6546059
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T11:39:42+00:00 2026-05-25T11:39:42+00:00

I’ve got some lines of information from a data-file in C++. One information is

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I’ve got some lines of information from a data-file in C++. One information is a 12 character long number. How can I convert this from string to long long (I think long long is most suitable for this) without data loss?

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  1. Editorial Team
    Editorial Team
    2026-05-25T11:39:43+00:00Added an answer on May 25, 2026 at 11:39 am

    In C++, there is no long long data type. It’s available in C99. However, you can use int64_t. Include <stdint.h>.

    Use boost::lexical_cast to convert string into int64_t.

    Or you can write a convert function yourself as:

    int64_t convert(const std::string &s)
    {
       if(s.size() == 0 ) 
           std::runtime_error error("invalid argument");
       int64_t v = 0;
       size_t i=0;
       char sign = (s[0] == '-' || s[0] == '+') ? (++i, s[0]) : '+';
       for( ; i < s.size(); ++i)
       {
          if ( s[i] < '0' || s[i] > '9' )
              throw std::runtime_error("invalid argument");
          v = v * 10 + s[i] - '0';
       }
       return sign == '-' ? -v : v;
    }
    

    Test code:

    int main() {
            try{
               std::cout << convert("68768768") << std::endl;
               std::cout << convert("+68768768") << std::endl;
               std::cout << convert("-68768768") << std::endl;
               std::cout << convert("68768768x") << std::endl;
            }catch(const std::exception &e)
            {
               std::cout << e.what() << std::endl;
            }
            return 0;
    }
    

    Output:

    68768768
    68768768
    -68768768
    invalid argument
    

    Online demo : http://ideone.com/nnSLp

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