Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 749011
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T14:23:09+00:00 2026-05-14T14:23:09+00:00

I’ve got some SQL that used to work with an older MySQL version, but

  • 0

I’ve got some SQL that used to work with an older MySQL version, but after upgrading to a newer MySQL 5 version, I’m getting an error. Here’s the SQL:

SELECT portfolio.*, projects.*, types.*
FROM projects, types
LEFT JOIN portfolio
ON portfolio.pfProjectID = projects.projectID
WHERE projects.projectType = types.typeID AND types.typeID = #URL.a#
ORDER BY types.typeSort, projects.projectPriority ASC

and the new error I’m receiving:

Unknown column 'projects.projectID' in 'on clause'

How can I convert this to compatible SQL for the newer MySQL version?

Thanks very much!

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-14T14:23:10+00:00Added an answer on May 14, 2026 at 2:23 pm

    You need to rewrite the query using INNER JOIN instead of comma operator:

    SELECT portfolio.*, projects.*, types.*
    FROM projects
    INNER JOIN types
    ON projects.projectType = types.typeID
    LEFT JOIN portfolio
    ON portfolio.pfProjectID = projects.projectID
    WHERE types.typeID = #URL.a#
    ORDER BY types.typeSort, projects.projectPriority ASC
    

    Explanation:

    This has to do with MySQL changing operator precedence to comply with ANSI standards. Check out the MySQL documentation: http://dev.mysql.com/doc/refman/5.1/en/join.html

    INNER JOIN and , (comma) are
    semantically equivalent in the absence
    of a join condition: both produce a
    Cartesian product between the
    specified tables (that is, each and
    every row in the first table is joined
    to each and every row in the second
    table).

    However, the precedence of the comma
    operator is less than of INNER JOIN,
    CROSS JOIN, LEFT JOIN, and so on. If
    you mix comma joins with the other
    join types when there is a join
    condition, an error of the form
    Unknown column ‘col_name’ in ‘on
    clause’ may occur. Information about
    dealing with this problem is given
    later in this section.

    There is also more detailed explanation on MySQL page, search for “Previously, the comma operator (,)”

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 531k
  • Answers 531k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer Use pdftk. To remove page 8: pdftk in.pdf cat 1-7… May 16, 2026 at 11:56 pm
  • Editorial Team
    Editorial Team added an answer You can use .next() since it's the next (immediate next,… May 16, 2026 at 11:56 pm
  • Editorial Team
    Editorial Team added an answer Make your Button a field, and modify its size in… May 16, 2026 at 11:56 pm

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Related Questions

I've got a string that has curly quotes in it. I'd like to replace
i got an object with contents of html markup in it, for example: string
I have just tried to save a simple *.rtf file with some websites and
I want to count how many characters a certain string has in PHP, but
link Im having trouble converting the html entites into html characters, (&# 8217;) i
Seemingly simple, but I cannot find anything relevant on the web. What is the
I have a JSP page retrieving data and when single or double quotes are
Does anyone know how can I replace this 2 symbol below from the string
this is what i have right now Drawing an RSS feed into the php,
I'm trying to decode HTML entries from here NYTimes.com and I cannot figure out

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.