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Home/ Questions/Q 7965601
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T06:12:25+00:00 2026-06-04T06:12:25+00:00

I’ve got the following code: #include <stdio.h> int main(int argc, char **argv) { int

  • 0

I’ve got the following code:

#include <stdio.h>
int main(int argc, char **argv) {
    int i = 0;
    (i+=10)+=10;
    printf("i = %d\n", i);
    return 0;
}

If I try to compile it as a C source using gcc I get an error:

error: lvalue required as left operand of assignment

But if I compile it as a C++ source using g++ I get no error and when i run the executable:

i = 20

Why the different behavior?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T06:12:26+00:00Added an answer on June 4, 2026 at 6:12 am

    Semantics of the compound assignment operators is different in C and C++:

    C99 standard, 6.5.16, part 3:

    An assignment operator stores a value in the object designated by the left operand. An
    assignment expression has the value of the left operand after the assignment, but is not an
    lvalue.

    In C++ 5.17.1:

    The assignment operator (=) and the compound assignment operators all group right-to-left. All require a modifiable
    lvalue as their left operand and return an lvalue with the type and value of the left operand after the assignment has taken place.

    EDIT : The behavior of (i+=10)+=10 in C++ is undefined in C++98, but well defined in C++11. See this answer to the question by NPE for the relevant portions of the standards.

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