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Home/ Questions/Q 3596098
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T19:56:25+00:00 2026-05-18T19:56:25+00:00

I’ve got the following code on my site: <!– Boat weather widget –> <div

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I’ve got the following code on my site:

<!-- Boat weather widget -->
<div id="boat_weather_tab_container">
    <div id="boat_weather_tab">
        <script type="text/javascript" src="widget.js"></script>
    </div>
    <div id="boat_weather_tab_button">
        <img src="images/blank150.gif">
    </div>
</div>

<script type="text/javascript">
$(document).ready(function(){
    $("#boat_weather_tab_button").click(function(){
        // boat_weather_tab_hidden = 1 on page load
        if (boat_weather_tab_hidden) {
            $("#boat_weather_tab").animate({
                marginTop: "-1px"
            }, 500);
            boat_weather_tab_hidden = 0;
        } else {
            $("#boat_weather_tab").animate({
                marginTop: "-254px"
            }, 500);
            boat_weather_tab_hidden = 1;
        }
    });
});
</script>

Now the client wants #boat_weather_tab to slide back up not just when #boat_weather_tab_button is clicked, but when the user clicks anywhere else on the page, which I understand to be the equivalent of when the parent container div #boat_weather_tab_container loses focus.

What is the jQuery I would need to accomplish this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T19:56:26+00:00Added an answer on May 18, 2026 at 7:56 pm

    Maybe

    $(document).click(function(event)
    {
     if(boat_weather_tab_hidden==0 && $("#boat_weather_tab").queue()==0 )
     {
       $("#boat_weather_tab").animate({
                    marginTop: "-254px"
                }, 500);
                boat_weather_tab_hidden = 1;
    
     }
    });
    

    Not tested, but the idea is the document click will now only hide the boat when it is not currently animating

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