Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 897365
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T14:52:36+00:00 2026-05-15T14:52:36+00:00

I’ve got the following method I created which works fine if there actually is

  • 0

I’ve got the following method I created which works fine if there actually is the delimiter in question. I want to keep this out of LINQ for now…

e.g.

If I pass in the string “123;322;323” it works great.

But if I only pass in one string value without the delimiter such as “123” it obviously is not going to split it since there is no delimiter. I am just trying to figure out the best way to check and account for this and be able to spit out that one value back in the list

public static List<int> StringToList(string stringToSplit, char splitDelimiter)
{
    List<int> list = new List<int>();

    if (string.IsNullOrEmpty(stringToSplit))
        return list;

    string[] values = stringToSplit.Split(splitDelimiter);

    if (values.Length < 1)
        return list;

    foreach (string s in values)
    {
        int i;
        if (Int32.TryParse(s, out i))
            list.Add(i);
    }

    return list;
}

UPDATED: This is what I came up with that seems to work but sure is long

    public static List<int> StringToList(string stringToSplit, char splitDelimiter)
    {
        List<int> list = new IntList();

        if (string.IsNullOrEmpty(stringToSplit))
            return list;

        if (stringToSplit.Contains(splitDelimiter.ToString()))
        {
            string[] values = stringToSplit.Split(splitDelimiter);

            if (values.Length <= 1)
                return list;

            foreach (string s in values)
            {
                int i;
                if (Int32.TryParse(s, out i))
                    list.Add(i);
            }
        }
        else if (stringToSplit.Length > 0)
        {
            int i;
            if(Int32.TryParse(stringToSplit, out i))
                list.Add(i);
        }

        return list;
    }
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T14:52:37+00:00Added an answer on May 15, 2026 at 2:52 pm

    There are a LOT of unnecessary checks for conditions that don’t matter to the core logic of the method.

    public static List<int> StringToList(string stringToSplit, char splitDelimiter) 
    { 
        List<int> list = new IntList(); 
    
        if (string.IsNullOrEmpty(stringToSplit)) 
            return list; 
    
        //this if is not necessary. As others have said, Split will return a string[1] with the original string if no delimiter is found
        if (stringToSplit.Contains(splitDelimiter.ToString())) 
        { 
            string[] values = stringToSplit.Split(splitDelimiter); 
    
            //why check this? if there are no values, the foreach will do nothing and fall through to a return anyway.
            if (values.Length <= 1) 
                return list; 
    
            foreach (string s in values) 
            { 
                int i; 
                if (Int32.TryParse(s, out i)) 
                    list.Add(i); 
            } 
        } 
        //again, this is rendered redundant due to previous comments
        else if (stringToSplit.Length > 0) 
        { 
            int i; 
            if(Int32.TryParse(stringToSplit, out i)) 
                list.Add(i); 
        } 
    
        return list; 
    }
    

    Try this. You hopefully have some unit tests calling this method to make sure it works…right?

    public static List<int> StringToList(string stringToSplit, char splitDelimiter) 
    { 
        List<int> list = new IntList(); 
    
        if (string.IsNullOrEmpty(stringToSplit)) 
            return list;
    
        foreach(var s in stringToSplit.Split(splitDelimiter))
        {
            int i;
            if(int.TryParse(s, out i))
                list.Add(i);
        }
        return list;
    }
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a string like this: La Torre Eiffel paragonata all&#8217;Everest What PHP function
I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this
I want to count how many characters a certain string has in PHP, but
link Im having trouble converting the html entites into html characters, (&# 8217;) i
For some reason, after submitting a string like this Jack’s Spindle from a text
I am trying to understand how to use SyndicationItem to display feed which is
I used javascript for loading a picture on my website depending on which small
I've got a string that has curly quotes in it. I'd like to replace
this is what i have right now Drawing an RSS feed into the php,
I have this code to decode numeric html entities to the UTF8 equivalent character.

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.