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Home/ Questions/Q 7500949
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T20:22:07+00:00 2026-05-29T20:22:07+00:00

I’ve got the following method: protected <S> void setValue(final S oldValue, final S newValue)

  • 0

I’ve got the following method:

protected <S> void setValue(final S oldValue, final S newValue) {
    // Do something
}

I want to make sure, that both parameters are of the same type. It would be cool, if there’d be a compiler error when you try to pass parameters of two different types.

The above way is clearly not the correct one. I can put into a String and an Integer, since the both extend from Object.

Is my want even possible? Or is the only way to make sure both parameters are of the same type to check it inside the method and throw an IllegalArgumentException?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T20:22:09+00:00Added an answer on May 29, 2026 at 8:22 pm

    You can do that if you consider that S is the correct type :

    protected <S, T extends S> void setValue(final S oldValue, final T newValue) {
        // Do something
    }
    

    You can and can’t input these :

    // Works
    setValue("something", "something");
    setValue(new Object(), new String());
    
    // Doesn't work
    setValue(new String(), new Object());
    

    or

    You can do :

    protected <S> void setValue(final S oldValue, final S newValue, final Class<S> clazz) {
        // Do something
    }
    

    and use it like that

    setValue("something", "something", String.class);
    

    or

    protected <S> void setValue(final S oldValue, final S newValue) {
        if(!oldValue.getClass().equals(newValue.getClass())) {
            //throw something
        }
    }
    
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