I’ve got the following MySQL query / subquery:
SELECT id, user_id, another_id, myvalue, created, modified,
(
SELECT id
FROM users_values AS ParentUsersValue
WHERE ParentUsersValue.user_id = UsersValue.user_id
AND ParentUsersValue.another_id = UsersValue.another_id
AND ParentUsersValue.id < UsersValue.id
ORDER BY id DESC
LIMIT 1
) AS old_id
FROM users_values AS UsersValue
WHERE created >= '2009-12-20'
AND created <= '2010-01-21'
AND user_id = 9917
AND another_id = 23
Given the criteria listed, the result for the subquery (old_id) should be null (no matches would be found in my table). Instead of MySQL returning null, it just seems to drop the “WHERE ParentUsersValue.user_id = UsersValue.user_id” clause and pick the first value that matches the other two fields. Is this a MySQL bug, or is this for some reason the expected behavior?
Update:
CREATE TABLE users_values (
id int(11) NOT NULL AUTO_INCREMENT,
user_id int(11) DEFAULT NULL,
another_id int(11) DEFAULT NULL,
myvalue double DEFAULT NULL,
created datetime DEFAULT NULL,
modified datetime DEFAULT NULL,
PRIMARY KEY (id)
) ENGINE=InnoDB AUTO_INCREMENT=2801 DEFAULT CHARSET=latin1
EXPLAIN EXTENDED:
id select_type table type possible_keys key key_len ref rows filtered Extra
1 PRIMARY UsersValue index_merge user_id,another_id user_id,another_id 5,5 NULL 1 100.00 Using intersect(user_id,another_id); Using where
2 DEPENDENT SUBQUERY ParentUsersValue index PRIMARY,user_id,another_id PRIMARY 4 NULL 1 100.00 Using where
EXPLAIN EXTENDED Warning 1003:
select `mydb`.`UsersValue`.`id` AS `id`,`mydb`.`UsersValue`.`user_id` AS `user_id`,`mydb`.`UsersValue`.`another_id` AS `another_id`,`mydb`.`UsersValue`.`myvalue` AS `myvalue`,`mydb`.`UsersValue`.`created` AS `created`,`mydb`.`UsersValue`.`modified` AS `modified`,(select `mydb`.`ParentUsersValue`.`id` AS `id` from `mydb`.`users_values` `ParentUsersValue` where ((`mydb`.`ParentUsersValue`.`user_id` = `mydb`.`UsersValue`.`user_id`) and (`mydb`.`ParentUsersValue`.`another_id` = `mydb`.`UsersValue`.`another_id`) and (`mydb`.`ParentUsersValue`.`id` < `mydb`.`UsersValue`.`id`)) order by `mydb`.`ParentUsersValue`.`id` desc limit 1) AS `old_id` from `mydb`.`users_values` `UsersValue` where ((`mydb`.`UsersValue`.`another_id` = 23) and (`mydb`.`UsersValue`.`user_id` = 9917) and (`mydb`.`UsersValue`.`created` >= '2009-12-20') and (`mydb`.`UsersValue`.`created` <= '2010-01-21'))
This returns correct results (
NULL) for me:Could you please run this query:
and make sure it returns
1?Note that your subquery does not filter on
created, so the subquery can return values out of the range the main query defines.Update:
This is definitely a bug in
MySQL.Most probably the reason is that the access path chosen for
UsersValuesisindex_intersect.This selects appropriate ranges from both indexes and build their intersection.
Due to the bug, the dependent subquery is evaluated before the intersection completes, that’s why you get the results with the correct
another_idbut wronguser_id.Could you please check if the problem persists when you force
PRIMARYscan on theUsersValues:Also, for this query you should create a composite index on
(user_id, another_id, id)rather than two distinct indexes onuser_idandanother_id.Create the index and rewrite the query a little:
The
user_id DESC, another_id DESCclauses are logically redundant, but they will make the index to be used for ordering.