Question

I’ve got this code in my script, and it’s only showing me the first row..
Any solutions? (This is NOT my whole script)

    $sql = mysql_query ('select * from todo');
if (!$sql) {
    die('Invalid query: ' . mysql_error());
}
$taskrow = mysql_query ('select * from todo');
        if($_SERVER['REQUEST_METHOD'] == 'POST'){
    $taak = $_POST['taak'];
    $beschrijving = $_POST['beschrijving'];
    $categorie = $_POST['categorie'];
    $prioriteit = $_POST['prioriteit'];
    $datum = $_POST['datum'];
    $query = mysql_query("INSERT INTO todo (taak, beschrijving, categorie, prioriteit, datum) VALUES ('$taak', '$beschrijving', '$categorie', '$prioriteit', '$datum')") or die(mysql_error());
 } ?>

<?php $task = mysql_fetch_assoc($taskrow); ?>

<td><?php echo $task['taak']; ?></td>
<td><?php echo $task['beschrijving']; ?></td>
<td><?php echo $task['categorie']; ?></td>
<td><?php echo $task['prioriteit']; ?></td>
<td><?php echo $task['datum']; ?> </td>    

Answer 1

By doing:

$task = mysql_fetch_assoc($taskrow);

You are turning $task into an object, containing data from the rows selected in your DB query.

So, you need to loop through that object, in order to play with each row’s data…

So try:

while ($task = mysql_fetch_assoc($taskrow)){?>

<td><?php echo $task['taak'];?></td>
<td><?php echo $task['beschrijving']; ?> </td>
<td><?php echo $task['categorie']; ?></td>
<td><?php echo $task['prioriteit']; ?></td>
<td><?php echo $task['datum']; ?> </td>  
<? } ?>