Question

I’ve got this equation that I want to solve with a java application.

It looks like this

y*n-1 = y*n-2 + 1035 + [(n-1)^2 + (n-3)] * y
y*n   = y*n-1 + (n^2 * y)

So the user should input N and then the Java application should calculate how much Y is.
Is that somehow possible to do and if so, how?

Thanks in advance,
Michael.

EDIT:

Thanks to mprabhat, it looks like this right now but I’m still doing it wrong somehow..

   public class equation
   {


private static double solveFirstEquation(double n){
    double y =0;
    if(n > 0) {
        y = ((n -1) + Math.pow( n , 2))/ n;
    }
    return y;
}

private static double solveSecondEquation(double n){
    double y = 0;
    if(n > 1) {
        y = ((n-2)+ (Math.pow(n-1, 2) + n-3) + 1035)/(n-1);
    }
    return y;


}
public static void main(String args[])
{
System.out.println("How much is n?");
int n = 0;
n = Keyboard.readInt();
}
    }

I tried to put the “void main String args” in the top but that wouldn’t let me run the application.

Answer 1

Something like this :

import java.util.Scanner;

public class TestEquation {

private static double solveFirstEquation(double n) {
    double y = 0;
    if (n > 0) {
        y = ((n - 1) + Math.pow(n, 2)) / n;
    }
    return y;
}

private static double solveSecondEquation(double n) {
    double y = 0;
    if (n > 1) {
        y = ((n - 2) + (Math.pow(n - 1, 2) + n - 3) + 1035) / (n - 1);
    }
    return y;

}
public static void main(String args[]) {
    System.out.println("How much is n?");
    double n = 0;
    Scanner scanner = new Scanner(System.in);
    n = scanner.nextDouble();
    System.out.println(solveFirstEquation(n));
    System.out.println(solveSecondEquation(n));
}

}