Question

I’ve got three tables: Users, Roles, Authorites

Users

|username|lastName|firstName|....
|dan     |foo     |dan
|russ    |bar     |russ

Roles

|role                 |roleLevel
|ROLE_ADMIN           | 0
|ROLE_COMPANY_ADMIN   | 20
|ROLE_MARKETING_ADMIN | 50
|ROLE_SERVICE_ADMIN   | 80
|ROLE_USER            | 100

Authorities

|username|authority
|dan     |ROLE_SERVICE_ADMIN  |
|dan     |ROLE_USER           |
|russ    |ROLE_MARKETING_ADMIN|
|russ    |ROLE_ADMIN          |
|russ    |ROLE_COMPANY_ADMIN  |

I need to get all the DISTINCT users that have a roleLevel higher than the INT I pass in AND their lowest roleLevel

What I have now is:

SELECT DISTINCT u.username, u.firstName, u.lastName, r.roleLevel FROM AUTHORITIES a, ROLES r, USERS u
WHERE r.role =  a.authority
AND a.username = u.username 
AND r.roleLevel >= #{roleLevel} 
ORDER BY u.lastName, u.firstName

but that gives me multiple rows for users with multiple roles. How can I get the users with a lower roleLevel than what I passed in?

Answer 1

It gives you multiple rows because you haven’t specified that you want the lowest; plus you’ve used a greater than not a lower than.

SELECT u.username, u.firstName, u.lastName, min(r.roleLevel) minroleLevel
  FROM AUTHORITIES a, ROLES r, USERS u
 WHERE r.role =  a.authority
   AND a.username = u.username 
   AND r.roleLevel <= #{roleLevel}
 GROUP BY u.username, u.firstName, u.lastName 
 ORDER BY u.lastName, u.firstName